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A rotating table completes one rotation in 10 sec.and its moment of inertia is 100 kg-m2. A personof 50 kg. mass stands at the centre of the rotatingtable. If the person moves 2m from the centrethe angular velocity of the rotating table(in rad/sec). will be:2π(1)30 (2) 20m30 (3) 23 (4) 2T |
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Answer» Net torqe about the centre of rotation is zero hence angular monetum is conserved here. Therfore, I1w1 = I2w2 100*(2pi/10) =(100 + 50*4)*w 20pi = 300w2 w2 = 2pi/30 |
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