

InterviewSolution
Saved Bookmarks
1. |
A rubber ball of mass `50g` falls from a height of `100cm` and rebounds to a height of `50cm` Find the impulse and average force between the ball and the ground, if time of contact is `0.1s` . |
Answer» Correct Answer - `0.3778 Ns ; 3.78N` . Velocity on striking the ground `upsilon_(1) = sqrt(2 g h_(1)) = sqrt(2 xx 9.8 xx 1) = 4.427 m//s` velocity on rebouding `upsilon_(2) = sqrt(2 g h_(2))` `=sqrt(2 xx 9.8 xx (1)/(2)) = 3.13m//s` Impulse = change in linear momentum `= m upsilon _(1) - m (-upsilon_(2)) = m (upsilon_(1) + upsilon_(2))` `= 50 xx 10^(-3) (4.427 + 3.13) = 0.3778 Ns` `F = ("Impulse")/(t) = (0.3778)/(0.1) =3.78 N` . |
|