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A sample of oxygen at `NTP` has volume `V` and a sample of hydrogen at `NTP` has volume `4 V`. Both the gases are mixed and the mixture is maintained at `NTP` if the speed of sound in hydrogen at `NTP` is `1270 m//s`, that in the mixture will beA. `317 m//s`B. `635 m//s`C. `830 m//s`D. `950 m//s` |
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Answer» Correct Answer - B `rho_(max) = (rho_(O_(2)) V_(O_(2)) + rho_(H_(2)) V_(N_(2)))/(V_(O_(2)) + V_(H_(2)))` `= (16 xx V + 1 xx 4V)/(V + 4V)` `(v_("mix"))/(v_(H_(2))) = sqrt((rho_(H_(2)))/(rho_("mix"))) = sqrt((1)/(4)) = (1)/(2)` `v_("mix") = (v_(H_(2)))/(2) = (1270)/(2) = 635 m//s` |
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