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A sample of radioactive substance loses half of its activity in 4 days. The time in which its activity is reduced to 5% isA. (a) 12 daysB. (b) 8.3 daysC. (c) 17.3 daysD. (d) None of these |
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Answer» Correct Answer - C `lambda=(1n2)/(t_(1//2)) = (1n2)/(4) day^-1` Now, apply `R=R_0e^(-lambdat) implies 5=100e^(-lambdat)` Substituting value of `lambda`, we can find t. |
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