1.

A sample of radioactive substance loses half of its activity in 4 days. The time in which its activity is reduced to 5% isA. (a) 12 daysB. (b) 8.3 daysC. (c) 17.3 daysD. (d) None of these

Answer» Correct Answer - C
`lambda=(1n2)/(t_(1//2)) = (1n2)/(4) day^-1`
Now, apply
`R=R_0e^(-lambdat) implies 5=100e^(-lambdat)`
Substituting value of `lambda`, we can find t.


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