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InterviewSolution
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A sample of `U^(238) ("half life" = 4.5 xx 10^(9)yr)` ore is found to contain `23.8 g" of " U^(238) ` and `20.6g ` of `Pb^(206)`. Calculate the age of the ore |
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Answer» Correct Answer - [`4.5 xx 10^(9)` year] `U^(238) rarr Pb^(206)` `((20.6)/(206))=0.1 "mol present"` i.e. 0.1 mol of `U^(238)` decay `0.1 xx 238=(23.8)` decay Initial mass of `U^(238)=(23.8 +23.8)=47.6` 23.8 left and 23.8 decay time `t_(1//2)=4.5 xx 10^(9)` year |
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