1.

A scientist has developed a system which goes from P to Q by two different paths. Heat given to the system in path 1 is 1000 J. The work done by the system along path 1 is more than path 2 by 100 J. What is the heat exchanged by the system in path 2?

Answer»

For path 1:

Heat given Q1 = + 1000 J

Work done = W1(let)

For path 2:

Work done (W2) = (W1 − 100) J

Heat given Q2 = ?

As change in internal energy between two states for different paths is same.

∴ ∆U = Q1 − W1 = Q2 − W2

1000 – W1 = Q2 − (W1 − 100)

or  Q2 = (1000 – 100) J

= 900 J



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