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A scientist has developed a system which goes from P to Q by two different paths. Heat given to the system in path 1 is 1000 J. The work done by the system along path 1 is more than path 2 by 100 J. What is the heat exchanged by the system in path 2? |
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Answer» For path 1: Heat given Q1 = + 1000 J Work done = W1(let) For path 2: Work done (W2) = (W1 − 100) J Heat given Q2 = ? As change in internal energy between two states for different paths is same. ∴ ∆U = Q1 − W1 = Q2 − W2 1000 – W1 = Q2 − (W1 − 100) or Q2 = (1000 – 100) J = 900 J |
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