th of slit is 0.2 mm.Explanation:=> The DISTANCE between the first and third minima in diffraction PATTERN, x:x = x₂ - x₁ = 3 mm= 3 * 10⁻³ m=> The distance of a SCREEN from a single slit,  D:D = 50 cm = 0.5 mWavelength λ = 6000A° = 6000 * 10⁻¹⁰ m=> Now, x = λD/dx₂ - x₁ =(3λ - λ)D/dx₂ - x₁ = 2λD/dd = 2λD / x₂ - x₁d = 2*6000*10⁻¹⁰*0.5/3*10⁻³d = 2 * 10⁻⁴ md = 0.2 mmThus, the width of slit is 0.2 mm.Learn more: Q:1 Screen is placed 80 cm from a single slit, which is illuminated with 5600 A light. If distance between the first and second minima in the diffraction pattern is 1.49 mm. Then width of the slit will be?Click here: brainly.in/question/9415527Q:2 A beam of light of wavelength 600 nm from a distance source falls on a single slit 1 mm wide and the resulting diffraction pattern is observed on a screen 2m away. The distance between the first dark fringes on either side of the central bright fringe isA beam of light of wavelength 600 nm from a distance source falls on a single slit 1 mm wide and the resulting diffraction pattern is observed on a screen 2m away. The distance between the first dark fringes on either side of the central bright fringe isA beam of light of wavelength 600 nm from a distance source falls on a single slit 1 mm wide and the resulting diffraction pattern is observed on a screen 2m away. The distance between the first dark fringes on either side of the central bright fringe isA beam of light of wavelength 600 nm from a distance source falls on a single slit 1 mm wide and the resulting diffraction pattern is observed on a screen 2m away. The distance between the first dark fringes on either side of the central bright fringe is!Click here: brainly.in/question/1135201