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A second order reaction requires `70 min` to change the concentration of reactants form `0.08 M` to `0.01 M`. How much time will require to become `0.04 M` ?A. `10 min`B. `20 min`C. `30 min`D. `40 min` |
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Answer» Correct Answer - A For second order, when `(a-x) = 0.01 M` `k_(2) = (1)/(t).(x)/(a(a-x))` `k_(2) = (1)/(70). (0.07)/(0.08 xx 0.01)` …(i) When `(a-x) = 0.04 M` `k_(2) = (1)/(t).(0.04)/(0.08 xx 0.04)` …(ii) form Eqs. (i) and (ii), `(0.07)/(70 xx 0.08 xx 0.01) = (0.04)/(t xx 0.08 xx 0.04)` `rArr t = 10 min` |
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