1.

A segment of wire vibrates with fundamental frequency of 40 Hz under a tension of 9 kg-wt. Then, tension at which the fundamental frequency of the same wire becomes 900 Hz isA. 36 kg-wtB. 27 kg-wtC. 18 kg-wtD. 72 kg-wt

Answer» Correct Answer - a
Fundamental frequency, `n=1/(2l)sqrt(T/m)and nprop sqrt(T)`
`therefore n_(1)/n_(2)=sqrt(T_(1)/T_(2))rArr 450/900=sqrt(9/T_(2))`
`T_(2)=36` kg-wt


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