InterviewSolution
Saved Bookmarks
| 1. |
A shaft is turning at `65rad//s` at time zero. Thereafter, angular acceleration is given by `alpha=-10rad//s^(2)-5trad//s^(2)` Where `t` is the elapsed time (a). Find its angular speed at `t=3.0` s (b). How much angle does it turn in these `3s`?A. `25 rad//sec`B. `12.5 rad//sec`C. `17 rad//sec`D. `22 rad//sec` |
|
Answer» Correct Answer - B `omega=intalphadt` |
|