1.

A shell of mass 200 g is ejected from a gun of mass 4 kg by an explosion that generates 1.05 kJ of energy. The initial velocity of the shell is :​

Answer»

\small \bold{ \frac{E_1}{E_2}  =  \frac{m_2}{m_1}  \implies \frac{4}{0.2}  = 20 \implies \: E_2 =  \frac{E_1}{40} }

\bold{E_1 + E_2 = 1050 \: joule}

\small \bold{ \therefore \: E_1 =1000 \:  joule \: (energy \: of \: cell)}

\small\bold{ \therefore \: K.E. \: of \: shell =  \frac{1}{2}  \times m_1v {}^{2} _1}

\bold{1000 \times  \frac{1}{2}  \times (0.2) \times v {}^{2}  _1}

\bold{ \therefore \: V_1 =  \sqrt{10000}  = 100 \: m/s}



Discussion

No Comment Found

Related InterviewSolutions