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A ship of mass `3xx10^7kg` initially at rest, is pulled by a force of `5xx10^5N` through a distance of 3m. Assuming that the resistance due to water is negligible, the speed of the ship isA. `1.5m//sec`B. `60m//sec`C. `0.1m//sec`D. `5m//sec` |
Answer» Correct Answer - C `F=ma` `implies a=F/m=(5xx10^4)/(3xx10^7)=5/3xx10^-3ms^-2` Also, `v^2-u^2=2as` `impliesv^2-0^2=2xx5/3xx10^-3xx3=10^2` `impliesv=0.1ms^-1` |
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