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A ship of mass `3xx10^7kg` initially at rest, is pulled by a force of `5xx10^5N` through a distance of 3m. Assuming that the resistance due to water is negligible, the speed of the ship is |
Answer» Correct Answer - `0.1 ms^(-1)` Here, `m=3 xx 10^(7)kg, u=0, s=3m` `F =5 xx 10^(4) N, upsilon = ?` As `a = F//m = (5 xx 10^(4))/(3 xx 10^(7)) = (5)/(3) xx10^(-3) m//s^(2)` From `v^(2) - u^(2) = 2 as ` `v^(2) - 0 = 2 xx (5)/(3) xx 10^(-3) xx3 =10^(-2)` `v= 10^(-1) ms^(-1) = 0.1 ms^(-1)` . |
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