Saved Bookmarks
| 1. |
A simple harmonic motion is executed by a particle of mass 1 kg under a force of F. (36 Nm). If it crosses the centre of oscillation with a speed of 6 m/s, the amplitude of the motion is O (A) 1 m (B) 2 m (C) 0.5 m O (D) 1.5 m |
| Answer» CORRECT OPTION isAExplanation:0.6mM=0.1Kgf=−10x⇒k=10w= mk = 0.110 =10V MAX =6m/s⇒A= 106 =0.6mHence,theoptionAisthecorrectanswer. | |