1.

A simple harmonic oscillator has a period of 0.01 s and an amplitude of 0.2 m. The magnitude of the velocity in ms-1 at the centre of oscillation is​

Answer»

Answer:

LET EQUATION of SHM is x=Asin(ωt), Where A=0.2 m,

∴v=Aωcos(ωt),

∴ Velocity at mean POSITION v=Aω

Given, Time Period=0.01=

ω

⇒ω=200π

∴ Velocity=0.2×200π=40π



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