1.

A small ball of radius r rolls without sliding in a big hemispherical bowl. of radius R. what would be the ratio of the translational and rotaional kinetic energies at the bottom of the bowl.A. `2:1`B. `3:2`C. `4:3`D. `5:2`

Answer» Correct Answer - D
`(K.E._(T))/(K.E._(R))=(1/2 Mv^(2))/(1/2Iomega^(2))=(1/2Mv^(2))/(1/2 2/5 MR^(2)(v/R)^(2))=5:2`


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