1.

A small frictionless block slides with velocity 0.5 gr on the horizontal surface as shown in the Figure.The block leaves the surface at point C The angle θ in the Figure is

Answer»

The block leave contact where the normal reaction is zero so mv²/r = mgcosθ and v² = u²+2as so v² = 1/4gr + 2gr(1-cosθ) so 1/4 + 2(1-cosθ) = cosθ so 3cosθ = 9/4 so cosθ = 3/4 and θ = cos-¹(3/4).

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how you write v²

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