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A small frictionless block slides with velocity 0.5 gr on the horizontal surface as shown in the Figure.The block leaves the surface at point C The angle θ in the Figure is |
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Answer» The block leave contact where the normal reaction is zero so mv²/r = mgcosθ and v² = u²+2as so v² = 1/4gr + 2gr(1-cosθ) so 1/4 + 2(1-cosθ) = cosθ so 3cosθ = 9/4 so cosθ = 3/4 and θ = cos-¹(3/4). these don't seem to be class 10 questions unable to understand can understand them perfectly means how you write v² I will give questions which you will be solving for years yes now your grade is correct |
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