InterviewSolution
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InterviewSolution
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A small object is placed at distance of 3.6 cm from a magnifier of focal length 4.0 cm. a. find the position of theimage. B. find the linear magnification c. Find the angular magnification. |
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Answer» a. Using `1/v-1/u=1/f` 1/v=1/u+1/f=1-(-3.6cm)+1/(4.0cm)` or `v=-36cm` b. Linear magnification `=v/u` `9-36cm)/(-3.6cm)=10` c. If th object placed at a distance `u_0 form the lens, the angle subtended by the object on thelens is `beta=h/u_0` where h is the height of the object. The maximum angle subtended on the uN/Aided eye is `alpha=h/D` Thus, the angular magnification is `m=beta/alpha=D/u_0=(25cm)/(3.6cm)7.0` |
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