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A nearsighted man can clearly see objects up to a distance of 1.5m. Calculate the power of the lens of the spectacles necessary for the remedy of this defect. |
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Answer» The lens should form a virtul image of a distance object at 1.5 m form the lens. Thus, it should be a divergent lens andits focal length should be -1.5 m. Hence f-1.5 m `or P=1/f=-11.5m^-1=0.67D.` |
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