1.

A small stone of mass 200 g is tied to one end of a string of length 80 cm . Holding the other end in hand , the stone is whirled into a vertical circle What is the minimum speed that needs to be imparted at the lowest point of the circular path , so that the stone is just able to complete the vertical circle ? what would be the tension at the lowest point of circular path ? ` (Take g = 10 m//s^(2)) ` .

Answer» Here ,` m = 200 g = 0.2 kg , `
` l = r = 80 cm = 0.8 m , upsilon_(L) = ? T_(L) = ? `
From ` upsilon_(L) = sqrt(5 g r ) = sqrt(5 xx 10 xx 0.8 )= 6 .32 ms^(-1) `
` T_(L) = 6 mg = 6 xx 0.2 xx 10 = 12 N ` .


Discussion

No Comment Found

Related InterviewSolutions