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A soild block of mass 2 kg is resting inside a cube as shown in the figure .The cube is moving with a veocity `v=5thati +2hatj m//s` Here , t is is time in second the block is at rest with respect to the cube and cefficient of frision between the surface of ube and block is 0.6 then ,[take `g=10m//s^(2)`] A. force of friction acting on the block is 10 NB. force of friction acting on the block is 4 NC. the total force exerted by the block on the cube is `10sqrt(5) N`D. a,c |
Answer» Correct Answer - a,c |
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