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A solid iron rod has a cylindrical shape. Its height is 11 cm and base diameter is 7 cm. Then find the total volume of 50 rods. |
Answer» The height of the cylinderical Rod (h) = 11 cm, Radius (r) = 7/2 cm Volume = πr2h = \(\frac{22}{7}\times\frac{7}{2}\times\frac{7}{2}\) × 11 = 423.5 (cm)3 Volume of 50 rods = 50 × 423.5 = 21175 (cm)3 |
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