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A solid shell loses half of its weight in water. Relative density of shell is 5.0 What fraction of its volume is hollow ?

Answer» Correct Answer - `3//5`
Let x freaction of its volume be hollow. Then weight of the shell ` = (V - xV) xx(5.0 xx 10^3)xxg.` Weight of water displacedc `= V xx10^3 g` Loss in weight of shell = weight of water dispalced `:. (1)/(2) (V - xV) xx 5 xx10^3 xxg = Vxx 10^3 xx g` On solving `x = 3//5`


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