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A solution of `HCl` contains `0.1920 g` of an acid in `0.5 litre` of a solution. The degree of dissociation is `95%`. The `pH` of the solution isA. `4.0`B. `2.0`C. `2.192`D. `1.92` |
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Answer» Correct Answer - B Concentration `C` of `HCl` solution `=(0.1920)/(36.5xx0.5)=0.010 M` The degree of dissociation is `95%`, i.e., `= 0.95` Therefore, `[H^(+)]=0.010xx0.95=0.0095` `pH =-log[H^(+)]= -log(0.0095)` `= -[bar3.(9777)]=-(-2.02)=2.0` |
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