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A sound has an intensity of `2 xx 10^(-8) W//m^(2)`. Its intensity level in decibels is `(log_(10) 2 = 0.3)`A. `23`B. `3`C. `43`D. `4.3` |
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Answer» Correct Answer - C `L = 10 log_(10)((I)/(I_(0))) = 10 log_(10) ((2 xx 10^(-8))/(10^(-12)))` `= 10 log_(10) (2 xx 10^(4)) = 10[log_(10) 2 + log_(10) 10^(4)]` `= 10[0.3 + 4] = 43 dB` |
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