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A sound wave in air has a frequency of `300 H_(Z)` and a displacement ampulitude of `6.0 xx10^(-3) mm`. For this sound waves calculate the (a) Pressure ampulitude (b) intensity (c ) Sound intensity level (in dB) Speed of sound `= 344 m//s` and density of air `= 1.2 kg//m^(3)`. |
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Answer» Correct Answer - A::B::C::D `Delta p_(max) = Bak` `= (rho nu)^(2) (A)((omega)/(nu))` `= (2 pi f A rho nu)` `= (2 pi) (300)(6.0 xx 10^(-3)(1.2)(344)` `= 4.67 Pa` (b) `I = (nu(Deltap)^(2)max)/(2B)` `= ((Deltap)^(2)max)/(2 rho nu)` (as `B = rho nu^(2))` `= (4.67)^(2)/((2)(1.2)(344)` `= 0.0264 w//m^(2)` `= 2.64 xx 10^(-2) W//m^(2)` (c ) `L = log_(10) ((I)/(I_(0)))` `= 10 log_(10) ((2.64 xx 10^(-2))/(10^(-12)))` `= 104 dB` |
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