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A sound wave of frequency 440 Hz is passing through air. An `O_2` molecule (mass`=5.3xx10^(-26)Kg)` is set in oscillation with an amplitude of `10^-6m` speed at the centre of its oscillation is :A. `1.70xx10^(-6) m//s`B. `17.0xx10^(-6) m//s`C. `2.76 xx10^(-3) m//s`D. `2.77xx10^(-6) m//s` |
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Answer» Correct Answer - C `v_(max)=omega_(0)A` `=(2pif)A=(2pi)(440)(10^(-6))` `=2.76xx10^(-3) m//sec` |
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