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A sound wave of frequency 500 Hz covers a distance of 1000 m is 5 sec between the points X and Y. Then the number of waves between X and Y isA. 500B. 1000C. 2500D. 5000 |
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Answer» Correct Answer - C `V=1000/5=200 m//s` `V=n lambdarArr lambda=V/n=200/500` No. of wave `=L/(lambda)=(1000xx500)/200=2500` |
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