A sounding body emitting a frequency of `150 H_(Z)` is dropped from a height. During its fall under gravity it crosses a balloon moving upwards with a constant velocity of `2 m//s` one second after it started to fall . The difference in the frequency observer by the man in balloon just before and just afer crossing the body will be (velocity of sound `= 300 m//s`, `g = 10 m//s^(2))`A. 12B. 6C. 8D. 4

A sounding body emitting a frequency of `150 H_(Z)` is dropped from a

1.	A sounding body emitting a frequency of `150 H_(Z)` is dropped from a height. During its fall under gravity it crosses a balloon moving upwards with a constant velocity of `2 m//s` one second after it started to fall . The difference in the frequency observer by the man in balloon just before and just afer crossing the body will be (velocity of sound `= 300 m//s`, `g = 10 m//s^(2))`A. 12B. 6C. 8D. 4
Answer» Correct Answer - A `f=f_(0)((vpmv_(0))/(vpmv_(s)))` When approaching `f_(a)=150[(300+2)/(300-10)]` when receding `f_(r)=150[(300-2)/(300+10)]rArr f_(a)-f_(r)~=12` hence (A)

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