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A sphere liquid drop of radius R is divided into eight equal droplets. If surface tension is S, then the work done in this process will beA. `2pi R^(2)S`B. `3pi R^(2)S`C. `4pi R^(2)S`D. `2pi RS^(2)` |
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Answer» Correct Answer - C Volume of big drop = Volume of 8 small droplets `(4)/(3)pi R^(3) = 8 xx (4)/(3)pi R^(3) rArr r = R//2` Work done `= S xx (4pi r^(2) xx 8 - 4pi R^(2))` `= S xx 4pi ((R^(2))/(4) xx 8 - R^(2)) = 4pi R^(2)S` |
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