A sphere of diameter r is cut from a solid sphereof radius r such that

1.	A sphere of diameter r is cut from a solid sphereof radius r such that the centre of mass of remainingpart be at maximum distance from orginal centre then this distance is :1)r/22)r/33)r/14(4) none of these
Answer» 1 Secondary School Physics 5 points A sphere of diameter r is cut from a sphere of radius r such that the center of mass of the remaining mass be at maximum distance from original center then the distance is Advertisement Ask for details Follow Report byGazala216.04.2017 Answers kvnmurty See diagram. Let x = distance between COM from the original center of the sphere, after the small sphere is cut off from it. Let the density of the sphere be = dMass of big sphere (full) = 4/3 * π r³* dMass of the small sphere cut off from it = 4/3 π (r/2)³ dMass of the remaining object = 7/6 π r³ * d Position of the COM of the complete sphere = 0=>- x * 7/6 π r³ d + r/2 * 4/3π (r/2)³ * d = 0=> x = r / 14

A sphere of diameter r is cut from a solid sphereof radius r such that the centre of mass of remainingpart be at maximum distance from orginal centre then this distance is :1)r/22)r/33)r/14(4) none of these

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Secondary School

Physics

5 points

A sphere of diameter r is cut from a sphere of radius r such that the center of mass of the remaining mass be at maximum distance from original center then the distance is

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byGazala216.04.2017

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kvnmurty

See diagram.

Let x = distance between COM from the original center of the sphere, after the small sphere is cut off from it.

Let the density of the sphere be = dMass of big sphere (full) = 4/3 * π r³* dMass of the small sphere cut off from it = 4/3 *π (r/2)³ * dMass of the remaining object = 7/6 π r³ * d

Position of the COM of the complete sphere = 0=>- x * 7/6 π r³ d + r/2 * 4/3π (r/2)³ * d = 0=> x = r / 14

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