1.

A sphere of radius `100mm` shrinks to radius 98mm, then the approximatedecrease in its volume is(a)`12000pim m^3`(b) `80000 pim m^3`(C) `8000pim m^3`(d) `120pim m^3`

Answer» `v= (4/3 pi r^3)`
`r= 100 mm`
`del v = (4/3) pi (3r^2) del r `
`= 4 pi r^2 del r`
`del r = 98-100 = -2`
`r= 100mm`
`del v = 4 pi r (100)^2 xx (-2) `
`= -80000 pi mm^3`
`= 80000 pi mm^3`
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