1.

A spherical balloon is filled with 4500p cubic meters ofhelium gas. If a leak in the balloon causes the gas to escape at the rate of `72pi`cubic meters per minute, then the rate (in metersper minute) at which the radius of the balloon decreases 49 minutes after theleakage began is(1) `9/7`(2) `7/9`(3) `2/9`(4) `9/2`

Answer» `V_i = 4500 pi m^3`
`(d V_i)/(dt) = -72 pi m^3/(min)`
`V_(49 min) = 4500 pi - (72 pi xx 49) = 4500 pi - 3528 pi`
`= 972 pi m^3 `
`V= 4/3 pi r^3`
at 49 min,`972 = 4/3 xx pi xx r^3`
`r^3 = 3 xx 972/4`
`r= 3^2 = 9 m`
`(dv)/dt = 4/3 pi 3 r^2 (dr)/(dt)`
`- 72 pi = 4/3 pi xx 3 xx 81 (dr)/(dt)`
`(dr)/(dt) = -72/(4 xx 81) = -2/9`
option 2 is correct


Discussion

No Comment Found