Saved Bookmarks
| 1. |
If 2a+3b+6c = 0, then show that the equation `a x^2 + bx + c = 0` has atleast one real root between 0 to 1. |
|
Answer» `"Let "f(x) =(ax^(2))/(3)+(bx^(2))/(2)+cx` `f(0) =0 " " and" "f(1) =(a)/(3)+(b)/(2) +c =2a +3b +6c =0` `"if "" " f(0) =f(1) " then " f(x) =0 " for some value of " x in (0,1)` `rArr " "ax^(2) +bx +c =0` for at least one `x in (0,1)` |
|