1.

A spherical mirror has a radius of curvature -40 cm. An object ofsize 7 cm is placed 10 cm from it, what is the nature, size andposition of the image?

Answer»

Explanation:

Given that,

Height h=3cm

Distance u=−15cm

Radius = 10cm

Now, the focus

F=

2

r

f=

2

10

=5cm

Now, by using mirror equation

f

1

=

V

1

+

u

1

5

1

=

v

1

−

15

1

v

1

=

5

1

+

15

1

v=

4

15

cm

v=4cm

So, the image will be formed between focus and pole

Now, the magnification is

m=

u

−v

m=

15

4

Now,

m=

h

h

′

15

4

=

3

h

′

h

′

=

15

12

h

′

=0.8

Hence, the height of image is 0.8 cm and distance of image is 4 cm

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