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A stable dipositive ion and a dinnegative ion are isoelectrnic with an octet configuaration in the second shell of their atoms. Identify of the preceding and succeeding elements and write their electronic configurations. |
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Answer» Solution :LET the dipositive ion be `X^(+2)` and dinegative ion is `Y^(-2)`. The octet in the SECOND shell `to 2,8` The number of electrons in `X=10+2=12` The number of electrons in `Y=10-2=8` X is magneshium with an ELECTRONIC configuration 2, 8,2,Y is oxygen with a congfiguration 2,6. The element preceding magnesium is sodium and the succeeding one is aluminium. They have eletronic configuration `2,8,1, and 2,8,3`, respectively. The elements preceding and succeeding for oxygen are nitrogen and fluorine which have electronic configuration 2,5 and 2,7, respectively. |
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