InterviewSolution
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InterviewSolution
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A star initially has `10^(40) ` deuterons. It produces energy via the process `_(1)H^(2) + _(1)H^(2) + rarr _(1) H^(3) + p. `and `_(1)H^(2) + _(1)H^(3) + rarr _(2) He^(4) + n` .If the average power radiated by the state is `10^(16) W` , the deuteron supply of the star is exhausted in a time of the order of . The masses of the nuclei are as follows: `M(H^(2)) = 2.014 amu,` `M(p) = 1.007 amu, M(n) = 1.008 amu, M(He^(4)) = 4.001 amu`.A. `10^(6)s`B. `10^(8)s`C. `10^(12)s`D. `10^(16)s` |
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Answer» Correct Answer - C mass defect `._(Delta)m=0.026 "amu"` Energy released per reaction is `=0.026xx931.5 MeV=24.2 MeV` `=3.87xx10^(-12)J` Energy released by consuming `10^(40)` deuterons is `=3.87xx10^(-12)xx(10^(40))/(3)=12.9xx10^(28)J` Power=energy/time |
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