A steel wire of length 1m is stretched between two rigid supports. The wire is vibrating in its fundamental mode with a frequency 100 Hz. The maximum acceleration at the mid point of the wire is 986 `m//s^2` . Then the amplitude of vibration at the midpoint isA. 25 cmB. 0.5 cmC. 0.25 cmD. 50 cm

A steel wire of length 1m is stretched between two rigid supports. The

1.	A steel wire of length 1m is stretched between two rigid supports. The wire is vibrating in its fundamental mode with a frequency 100 Hz. The maximum acceleration at the mid point of the wire is 986 `m//s^2` . Then the amplitude of vibration at the midpoint isA. 25 cmB. 0.5 cmC. 0.25 cmD. 50 cm
Answer» Correct Answer - C `a_m = omega^2A therefore A=(a_m)/(omega^2)` = `(986)/(4pi^2xx100xx100) = (9.86xx100)/(4xxpi^2xx 100xx100)` =0.25cm

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A steel wire of length 1m is stretched between two rigid supports. The wire is vibrating in its fundamental mode with a frequency 100 Hz. The maximum acceleration at the mid point of the wire is 986 `m//s^2` . Then the amplitude of vibration at the midpoint isA. 25 cmB. 0.5 cmC. 0.25 cmD. 50 cm

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