A stone drops from the edge of the roof. If it!passes a window 2 metre

1.	A stone drops from the edge of the roof. If it!passes a window 2 metre high in 0.1 sec.How far is the roof above the top of the window.
Answer» The object is falling under gravity. As it is moving towards the earth, Its acceleration is +g. As it is dropped, It has initial velocity = 0 . The stone passes the window of 2m high in 0.1s . Let the distance between the roof and that window be " k " km and the time taken to reach that " k "m is t That is k = 1/2gt² ( From the second equation of motion) Given that, Stone passes through the window in 0.1 second. So it travels k+2 m in t + 0.1seconds . k + 2 = 1/2g(t+ 0.1)² Substituting the value of k, 1/2gt² + 2 = 1/2g(t²+0.01 + 0.2t) 1/2gt² - 1/2gt² + 2 = 0.005 g + 0.1gt 2 = 0.005 * 10 + 0.1(10)t 2= 0.05 + t 2 - 0.05 = t 1.95 = t. Therefore, The stone takes 1.95seconds to travel from roof to top of the window. Now, We have to find The distance between roof and top of the window ( k) k = 1/2(10)(t²)k = 5t² k = 5(1.95)²k = 19.0125 Therefore, The height of the roof above the top of the window is 19.0125m

A stone drops from the edge of the roof. If it!passes a window 2 metre high in 0.1 sec.How far is the roof above the top of the window.

Answer»

The object is falling under gravity. As it is moving towards the earth, Its acceleration is +g.

As it is dropped, It has initial velocity = 0 .

The stone passes the window of 2m high in 0.1s .

Let the distance between the roof and that window be " k " km and the time taken to reach that " k "m is t

That is k = 1/2gt² ( From the second equation of motion)

Given that, Stone passes through the window in 0.1 second.

So it travels k+2 m in t + 0.1seconds .

k + 2 = 1/2g(t+ 0.1)²

Substituting the value of k,

1/2gt² + 2 = 1/2g(t²+0.01 + 0.2t)

1/2gt² - 1/2gt² + 2 = 0.005 g + 0.1gt

2 = 0.005 * 10 + 0.1(10)t 2= 0.05 + t 2 - 0.05 = t 1.95 = t.

Therefore, The stone takes 1.95seconds to travel from roof to top of the window.

Now, We have to find The distance between roof and top of the window ( k)

k = 1/2(10)(t²)k = 5t² k = 5(1.95)²k = 19.0125

Therefore, The height of the roof above the top of the window is 19.0125m