a stone is allowed to fall from a tower of height 200 metre and at the

1.	a stone is allowed to fall from a tower of height 200 metre and at the same time another stone is projected vertically upward from the ground at a velocity of 20 metre per second calculate when and where the stone will meet
Answer» Answer: Explanation: STONE thrown from the tower u = 0 g = -10 m/s2 s = - (200- x) s= ut +1/2 at2 -(200 - x) = 0 - 1/2 10 X t2 ................................................. (1) For UPWARD direction, u = 20 m/s g = -10 m/s2 s = +x +x = 200 t - 1/2 10 t2 .............................................................(2) Substracting 1 and 2, we get, 200 = 20t t = 10s x = 20 X 10 - 1/2 X 10 X 10 (square) = 200 - 500 m = 300 m I don't know the answer Sorry

a stone is allowed to fall from a tower of height 200 metre and at the same time another stone is projected vertically upward from the ground at a velocity of 20 metre per second calculate when and where the stone will meet

Answer»

Answer:

Explanation:

STONE thrown from the tower

u = 0

g = -10 m/s2

s = - (200- x)

s= ut +1/2 at2

-(200 - x) = 0 - 1/2 10 X t2 ................................................. (1)

For UPWARD direction,

u = 20 m/s

g = -10 m/s2

s = +x

+x = 200 t - 1/2 10 t2 .............................................................(2)

Substracting 1 and 2, we get,

200 = 20t

t = 10s

x = 20 X 10 - 1/2 X 10 X 10 (square)

= 200 - 500 m

= 300 m

I don't know the answer

Sorry

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a stone is allowed to fall from a tower of height 200 metre and at the same time another stone is projected vertically upward from the ground at a velocity of 20 metre per second calculate when and where the stone will meet​

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a stone is allowed to fall from a tower of height 200 metre and at the same time another stone is projected vertically upward from the ground at a velocity of 20 metre per second calculate when and where the stone will meet