A stone is allowed to fall from the top of a tower 300 m height and at the same time another stone is projected vertically up from the ground with a velocity `100 m//s`. Find when and where the two stones meet?

A stone is allowed to fall from the top of a tower 300 m height and a

1.	A stone is allowed to fall from the top of a tower 300 m height and at the same time another stone is projected vertically up from the ground with a velocity `100 m//s`. Find when and where the two stones meet?
Answer» Height of the tower `h=300m` Suppose the two stones meet at a height x from Z ground after t second `t=(S_(r))/(u_(r)),u_(r)=u+0=u,S_(r)=h` `t=(h)/(u)=(300)/(100)=3sec` Height of the stone from the point of projection is `X=ut-(1)/(2 g t^(2))=100xx3-(1)/(2)xx9.8xx9=255.9m`

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A stone is allowed to fall from the top of a tower 300 m height and at the same time another stone is projected vertically up from the ground with a velocity `100 m//s`. Find when and where the two stones meet?

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