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InterviewSolution
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A stone is dropped from a height of 200m high and the same time another stone is thrown vertically with the velocity of 10m/s upward when and where the two stones will meet.Ans:let assume thats= the displacement of meeting of the two stone.or,s=200m.or,s=s¹+s²( displacement of stone 1 and stone 2)s¹=ut+½*at².=> 0*t+½*10*t²=>0+5t²=>5t²s²=ut+½*at²=>-10*t+½ (-10)*t²=>(-10t)+(-5t²)s=s¹+s²=>200=5t²+(-10t)+(-5t²)=>200=10t=>t=200/10=>t=20s |
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Answer» Answer: Downward Explanation: As you THROW stone UPWARDS due to gravitational FORCE it will come downwards |
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