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A stone is dropped from the top of the top of cliff reaches it foot in 4 s. calculate the height of the cliff and the velocity with which stone reaches the ground.(g=10m\s^2) ​

Answer» <html><body><p>h = 80 m,  v = 40 m/sExplanation:Givena stone is dropped from the top of the cliffTime taken for stone to reach the ground = 4sLet height be 'h' and final velocity be 'v'a = <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a> = 10m/s²As it is a freely falling body initial velocity is zero i.e., <a href="https://interviewquestions.tuteehub.com/tag/u-1435036" style="font-weight:bold;" target="_blank" title="Click to know more about U">U</a> = 0.We know thats = ut + 1/2 at²⇒h = ut + 1/2 at²     [ here <a href="https://interviewquestions.tuteehub.com/tag/displacement-956081" style="font-weight:bold;" target="_blank" title="Click to know more about DISPLACEMENT">DISPLACEMENT</a> of stone is height of the cliff]⇒h = 0 + 1/2 <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>*(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)²∴ h = 5*16 = 80 m∴ h = 80 mWe know thatv = u + at⇒v = 0 + 10*4∴v = 40 m/s</p></body></html>


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