1.

A stone is dropped into a deep well and isheard to hit the water 3.41 s after beingdropped. Determine the depth of the well.

Answer»

Given:

a = -9.8 m/s2

t = 3.41 s

vi = 0 m/s

Find:

d = ??d = vi*t + 0.5*a*t2d = (0 m/s)*(3.41 s)+ 0.5*(-9.8 m/s2)*(3.41 s)2

d = 0 m+ 0.5*(-9.8 m/s2)*(11.63 s2)

d = -57.0 m

(NOTE: the - sign indicates direction)



Discussion

No Comment Found

Related InterviewSolutions