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A stone is dropped into a deep well and isheard to hit the water 3.41 s after beingdropped. Determine the depth of the well. |
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Answer» Given: a = -9.8 m/s2 t = 3.41 s vi = 0 m/s Find: d = ??d = vi*t + 0.5*a*t2d = (0 m/s)*(3.41 s)+ 0.5*(-9.8 m/s2)*(3.41 s)2 d = 0 m+ 0.5*(-9.8 m/s2)*(11.63 s2) d = -57.0 m (NOTE: the - sign indicates direction) |
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