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A stone is thrown in vertically upwards direction with a velocity of 5m/s if the acceleration of stone during its motion is 10m/s'2 in the downward direction what will be the height attained by stone and how much time will it take to reach there? |
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Answer» max height = 1.25 m time taken = 0.5 sec . Explanation: g = -10 m/s² u = 5 m/s v = 0 . v² - u² = 2gh => 0² - 5² = 2(-10)H => -25 = -20h => h = 25/20 = 1.25 m . therefore, max height attained = h = 1.25 m . v = u + gt => 0 = 5 + (-10)t => 10T = 5 => t = 5/10 = 0.5 sec . therefore, time taken to reach max height = t = 0.5 sec . Hope this helps :) |
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