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a stone is thrown vertically upward with a initial velocity of 5m|s find the maximum's distance |
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Answer» U= 5 m/sv= 0 m/s (since we need to find maximum height)a= -9.8 m/s^2s= (v^2 - u^2)/2a= (0-25)/-19.6 = -25/19.6 = 1.27mThus the maximum height reached by the stone is 1.27m. |
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