A stone is thrown vertically upward with a velocity of 5 m/s from a wa

1.	A stone is thrown vertically upward with a velocity of 5 m/s from a wall of height 5m. what will be the total distance travelled by stone before hitting the ground ?
Answer» ANSWER - ☞Given - u = 5m/s s = 5m a = g = -10 m/s² where $\longrightarrow$ u is initial velocity. $\longrightarrow$ s is HEIGHT of wall. $\longrightarrow$ a is acceleration due to GRAVITY. ━━━━━━━━━━━━━ ☞To find - Total distance ━━━━━━━━━━━━━ ☞Solution - Maximum height attained by stone - u = 5m/s V = 0 a = g = -10 m/s² where $\longrightarrow$ u is initial velocity. $\longrightarrow$ v is final velocity. $\longrightarrow$ a is acceleration due to gravity. By 3rd equation of motion of - $\sf v² = u² + 2as$ $\sf 0 = 5² - 2 × 10 × s$ $\sf 20s = 25$ $\sf s = 1.25m$ ━━━━━━━━━━━━━ Maximum height attained by stone is 1.25 m above the wall of 5m Distance from ground to max. height $\implies$ 1.25 + 5 $\implies$ 6.25 m ━━━━━━━━━━━━━ After REACHING the maximum height the stone will come to ground and will cover the same distance from ground to max. height. Distance from max. height to ground = 6.25m ━━━━━━━━━━━━━ $\longrightarrow$ Total distance = Distance from ground to max. height + Distance from max. height to ground Total distance = 6.25 + 6.25 Total distance covered by stone = 12.5 m ━━━━━━━━━━━━━ Thanks

A stone is thrown vertically upward with a velocity of 5 m/s from a wall of height 5m. what will be the total distance travelled by stone before hitting the ground ?

Answer»

ANSWER -

☞Given -

u = 5m/s

s = 5m

a = g = -10 m/s²

where

$\longrightarrow$ u is initial velocity.

$\longrightarrow$ s is HEIGHT of wall.

$\longrightarrow$ a is acceleration due to GRAVITY.

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☞To find -

Total distance

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☞Solution -

Maximum height attained by stone -

u = 5m/s

V = 0

a = g = -10 m/s²

where

$\longrightarrow$ u is initial velocity.

$\longrightarrow$ v is final velocity.

$\longrightarrow$ a is acceleration due to gravity.

By 3rd equation of motion of -

$\sf v² = u² + 2as$

$\sf 0 = 5² - 2 × 10 × s$

$\sf 20s = 25$

$\sf s = 1.25m$

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Maximum height attained by stone is 1.25 m above the wall of 5m

Distance from ground to max. height

$\implies$ 1.25 + 5

$\implies$ 6.25 m

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After REACHING the maximum height the stone will come to ground and will cover the same distance from ground to max. height.

Distance from max. height to ground = 6.25m

━━━━━━━━━━━━━

$\longrightarrow$ Total distance = Distance from ground to max. height + Distance from max. height to ground

Total distance = 6.25 + 6.25

Total distance covered by stone = 12.5 m

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