1.

A stone is thrown vertically upwards with a speed of 49 m/s. Then the velocity of the stone, one second before it reaches the maximum height is ?a) 4.9 m/sb) 9.8 m/sc) 13.6 m/sd) 19.6 m/s

Answer»

time t = (v-u )/a = (0-49)/(- 9.8) = 5 t’ = 5 – 1 = 4 v’ = u + at’ = 49 – (9.8) * 4 = 9.8 m/s. ∴ The velocity is 9.8 m/s.



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