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A stone is thrown vertically upwards with an initial speed `u` from the top of a tower, reaches the ground with a speed `3 u`. The height of the tower is :A. `(3u^(2))/(g)`B. `(4u^(2))/(g)`C. `(6u^(2))/(g)`D. `(9mu^(2))/(g)` |
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Answer» Correct Answer - B `v^(2)=u^(2)+2gh` `h=(v^(2)-u^(2))/(2g)=(9u^(2)-u^(2))/(2g)=(4u^(2))/(g)` |
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