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A stone of mass 0.05 kg is thrown vertically upwards. What is the direction and magnitude of net force on the stone during its upward motion?A. 0.98 N vertically downwardsB. 0.49 N vertically downwardsC. 9.8 N vertically downwardsD. 0.49 N vertically upwards |
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Answer» Correct Answer - B (b) Given, m=0.05 kg We know that, net force acting on a stone, `f_(g)=mg=0.05xx(-9.8)="-0.49N"` =0.49 N vertically downwards |
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